$\begin{equation*} \begin{cases} \frac{4x - 5}{5x + 2y} = 1 &\\ \frac{3 - 2x}{1 + 4y} = \frac{1}{5} & \end{cases} \end{equation*}$
$\begin{equation*} \begin{cases} 4x - 5 = 5x + 2y &\\ 5(3 - 2x) = 1 + 4y & \end{cases} \end{equation*}$
$\begin{equation*} \begin{cases} 4x - 5 = 5x + 2y &\\ 15 - 10x = 1 + 4y & \end{cases} \end{equation*}$
$\begin{equation*} \begin{cases} 4x - 5x - 2y = 5 &\\ 10x - 4y = 1 - 15 & \end{cases} \end{equation*}$
$\begin{equation*} \begin{cases} -x - 2y = 5 | * (-2) &\\ 10x - 4y = -14 & \end{cases} \end{equation*}$
$\begin{equation*} \begin{cases} 2x + 4y = -10 &\\ 10x - 4y = -14 & \end{cases} \end{equation*}$
2x + 4y + 10x − 4y = −10 − 14
12x = −24
x = −24 : 12
x = −2
−x − 2y = 5
2y = −x − 5
y = −0,5x − 2,5
y = −0,5 * (−2) − 2,5
y = 1 − 2,5
y = −1,5
Ответ: (−2;−1,5)