Дана функция y = f(x), где f(x) = 5x + 6. Найдите:
а) $f(\frac{1}{4}), f(-3), f(0,5), f(6\frac{2}{5})$;
б) $f(p), f(-2p), f(\frac{3}{5}p), -f(5p)$;
в) $f(a + 1), f(5 - a), f(a) - 6, f(\frac{a}{10}) - 3$;
г) $f(a - 3) + 1, f(a + 4) - 2, f(1 - 2a), -f(\frac{a + 6}{5})$.
$f(\frac{1}{4}) = 5 * \frac{1}{4} + 6 = \frac{5}{4} + 6 = 1\frac{1}{4} + 6 = 7\frac{1}{4}$
$f(-3) = 5 * (-3) + 6 = -15 + 6 = -9$
$f(0,5) = 5 * 0,5 + 6 = 2,5 + 6 = 8,5$
$f(6\frac{2}{5}) = 5 * 6\frac{2}{5} + 6 = 5 * \frac{32}{5} + 6 = 32 + 6 = 38$
f(p) = 5p + 6
f(−2p) = 5 * (−2p) + 6 = −10p + 6
$f(\frac{3}{5}p) = 5 * \frac{3}{5}p + 6 = 3p + 6$
$-f(5p) = -(5 * 5p + 6) = -(25p - 6) = -25p - 6$
f(a + 1) = 5(a + 1) + 6 = 5a + 5 + 6 = 5a + 11
f(5 − a) = 5(5 − a) + 6 = 25 − 5a + 6 = 31 − 5a
f(a) − 6 = 5a + 6 − 6 = 5a
$f(\frac{a}{10}) - 3 = 5 * \frac{a}{10} + 6 - 3 = \frac{a}{2} + 3$
f(a − 3) + 1 = 5(a − 3) + 6 + 1 = 5a − 15 + 7 = 5a − 8
f(a + 4) − 2 = 5(a + 4) + 6 − 2 = 5a + 20 + 4 = 5a + 24
f(1 − 2a) = 5(1 − 2a) + 6 = 5 − 10a + 6 = 11 − 10a
$-f(\frac{a + 6}{5}) = -(5 * \frac{a + 6}{5} + 6)= -(a + 6 + 6) = -(a + 12) = -a - 12$
Пожауйста, оцените решение
