Упростите выражение:
1) $0,42ac^3 * 1\frac{3}{7}a^4c^2$;
2) $1,2xyz * 2\frac{1}{6}x^5y^6$;
3) $-2\frac{1}{3}m^2np^3 * (\frac{3}{7}np^4)^2$;
4) $(1\frac{1}{2}x^2y^3)^5 * \frac{16}{27}x^8y^2$.
$0,42ac^3 * 1\frac{3}{7}a^4c^2 = \frac{42}{100}ac^3 * \frac{10}{7}a^4c^2 = \frac{21}{50} * \frac{10}{7}a^5c^5 = \frac{3}{5} * \frac{1}{1}a^5c^5 = 0,6a^5c^5$
$1,2xyz * 2\frac{1}{6}x^5y^6 = \frac{12}{10}xyz * \frac{13}{6}x^5y^6 = \frac{6}{5} * \frac{13}{6}x^6y^7z = \frac{1}{5} * \frac{13}{1}x^6y^7z = \frac{13}{5}x^6y^7z = 2,6x^6y^7z$
$-2\frac{1}{3}m^2np^3 * (\frac{3}{7}np^4)^2 = -\frac{7}{3}m^2np^3 * \frac{9}{49}n^2p^8 = -\frac{1}{1} * \frac{3}{7}m^2n^3p^{11} = -\frac{3}{7}m^2n^3p^{11}$
$(1\frac{1}{2}x^2y^3)^5 * \frac{16}{27}x^8y^2 = \frac{243}{32}x^{10}y^{15} * \frac{16}{27}x^8y^2 = \frac{9}{2} * \frac{1}{1}x^{18}y^{17} = 4,5x^{18}y^{17}$
Пожауйста, оцените решение
