Решите уравнение:
а) $x^2 + 8x = 0$;
б) $5x^2 - x = 0$;
в) $6y^2 - 30y = 0$;
г) $3x^2 - 1,2x = 0$;
д) $6x^2 - 0,5x = 0$;
е) $\frac{1}{4}y^2 + y = 0$;
ж) $x - 10x^2 = 0$;
з) $6x - 0,2x^2 = 0$;
и) $y^2 + \frac{2}{3}y = 0$.
$x^2 + 8x = 0$
x(x + 8) = 0
$x_1 = 0$
x + 8 = 0
$x_2 = -8$
$5x^2 - x = 0$
x(5x − 1) = 0
$x_1 = 0$
5x − 1 = 0
5x = 1
$x_2 = \frac{1}{5}$
$6y^2 - 30y = 0$
6y(y − 5) = 0
6y = 0
$y_1 = 0$
y − 5 = 0
$y_2 = 5$
$3x^2 - 1,2x = 0$
3x(x − 0,4) = 0
3x = 0
$x_1 = 0$
x − 0,4 = 0
$x_2 = 0,4$
$6x^2 - 0,5x = 0$
0,5x(12x − 1) = 0
0,5x = 0
$x_1 = 0$
12x − 1 = 0
12x = 1
$x_2 = \frac{1}{12}$
$\frac{1}{4}y^2 + y = 0$
$y(\frac{1}{4}y + 1) = 0$
$y_1 = 0$
$\frac{1}{4}y + 1 = 0$
$\frac{1}{4}y = -1$
$y_2 = -4$
$x - 10x^2 = 0$
x(1 − 10x) = 0
$x_1 = 0$
1 − 10x = 0
−10x = −1
$x_2 = 0,1$
$6x - 0,2x^2 = 0$
0,2x(30 − x) = 0
0,2x = 0
$x_1 = 0$
30 − x = 0
−x = −30
$x_2 = 30$
$y^2 + \frac{2}{3}y = 0$
$y(y + \frac{2}{3}) = 0$
$y_1 = 0$
$y + \frac{2}{3} = 0$
$y_2 = -\frac{2}{3}$
Пожауйста, оцените решение