Упростите:
а) $2(a^2 - 1)^2 - (a^2 + 3)(a^2 - 3) - \frac{1}{2}(a^2 + a - 4)(2a^2 + 3)$;
б) $4(m^3 - 3)^2 - (m^2 - 6)(m^2 + 6) - 9(8 - m + m^2)(1 - m)$.
$2(a^2 - 1)^2 - (a^2 + 3)(a^2 - 3) - \frac{1}{2}(a^2 + a - 4)(2a^2 + 3) = 2(a^4 - 2a^2 + 1) - (a^4 - 9) - \frac{1}{2}(2a^4 + 3a^2 + 2a^3 + 3a - 8a^2 - 12) = 2a^4 - 4a^2 + 2 - a^4 + 9 - a^4 - 1,5a^2 - a^3 - 1,5a + 4a^2 + 6 = -a^3 - 1,5a^2 - 1,5a + 17$
$4(m^3 - 3)^2 - (m^2 - 6)(m^2 + 6) - 9(8 - m + m^2)(1 - m) = 4(m^6 - 6m^3 + 9) - (m^4 - 36) - 9(8 - 8m - m + m^2 + m^2 - m^3) = 4m^6 - 24m^3 + 36 - m^4 + 36 - 9(8 - 9m + 2m^2 - m^3) = 4m^6 - 24m^3 - m^4 + 72 - 72 + 81m - 18m^2 + 9m^3 = 4m^6 - m^4 - 15m^3 - 18m^2 + 81m$
Пожауйста, оцените решение
