Найдите корень уравнения:
а) $\frac{1}{3}y + 2 = 1$;
б) $\frac{1}{5}x + 11 = 1 - \frac{3}{5}x$;
в) $8 - \frac{1}{4}z = 1$;
г) $3 - \frac{5}{7}t = 1 - \frac{3}{7}t$;
д) $\frac{1}{8}u - 2 = \frac{5}{8}u + 1$;
е) $\frac{2}{5}z - 7 = 3$.
$\frac{1}{3}y + 2 = 1$
$\frac{1}{3}y = 1 - 2$
$\frac{1}{3}y = -1$
$y = -1 : \frac{1}{3}$
y = −1 * 3
y = −3
$\frac{1}{5}x + 11 = 1 - \frac{3}{5}x$
$\frac{1}{5}x + \frac{3}{5}x = 1 - 11$
$\frac{4}{5}x = -10$
$x = -10 : \frac{4}{5}$
$x = -10 * \frac{5}{4}$
$x = -\frac{25}{2} = -12,5$
$8 - \frac{1}{4}z = 1$
$-\frac{1}{4}z = 1 - 8$
$-\frac{1}{4}z = -7$
$z = -7 : (-\frac{1}{4})$
z = 7 * 4
z = 28
$3 - \frac{5}{7}t = 1 - \frac{3}{7}t$
$-\frac{5}{7}t + \frac{3}{7}t = 1 - 3$
$-\frac{2}{7}t = -2$
$t = -2 : (-\frac{2}{7})$
$t = -2 * (-\frac{7}{2})$
t = 7
$\frac{1}{8}u - 2 = \frac{5}{8}u + 1$
$\frac{1}{8}u - \frac{5}{8}u = 1 + 2$
$-\frac{1}{2}u = 3$
$u = 3 : (-\frac{1}{2})$
u = 3 * (−2)
u = −6
$\frac{2}{5}z - 7 = 3$
$\frac{2}{5}z = 3 + 7$
$\frac{2}{5}z = 10$
$z = 10 : \frac{2}{5}$
$z = 10 * \frac{5}{2}$
z = 5 * 5
z = 25
Пожауйста, оцените решение