Решите уравнение:
а) $(x + 3)^2 - x^2 = 33$;
б) $x^2 - (x - 5)^2 = 10$;
в) $(x + 12)^2 = x(x + 8)$;
г) $(x - 3)(x + 1) = (x - 2)^2$.
$(x + 3)^2 - x^2 = 33$
$x^2 + 6x + 9 - x^2 = 33$
6x = 33 − 9
6x = 24
x = 4
$x^2 - (x - 5)^2 = 10$
$x^2 - (x^2 - 10x + 25) = 10$
$x^2 - x^2 + 10x - 25 = 10$
10x = 10 + 25
10x = 35
x = 3,5
$(x + 12)^2 = x(x + 8)$
$x^2 + 24x + 144 = x^2 + 8x$
$x^2 - x^2 + 24x - 8x = -144$
16x = −144
x = −9
$(x - 3)(x + 1) = (x - 2)^2$
$x^2 - 3x + x - 3 = x^2 - 4x + 4$
$x^2 - x^2 - 2x + 4x = 4 + 3$
2x = 7
x = 3,5
Пожауйста, оцените решение
