Найдите значение выражения:
а) $(1\frac{1}{4} + 1\frac{2}{3} - \frac{7}{12}) : 1\frac{1}{6}$;
б) $2\frac{4}{15} - 4\frac{1}{5} * (1\frac{5}{6} - \frac{41}{42})$;
в) $(\frac{2}{15} + 1\frac{7}{12}) * \frac{30}{103} - 2 : 2\frac{1}{4} * \frac{9}{32}$;
г) $(3\frac{1}{2} : 4\frac{2}{3} + 4\frac{2}{3} : 3\frac{1}{2}) * 4\frac{4}{5}$.
$(1\frac{1}{4} + 1\frac{2}{3} - \frac{7}{12}) : 1\frac{1}{6} = (1\frac{3}{12} + 1\frac{8}{12} - \frac{7}{12}) : \frac{7}{6} = (2\frac{11}{12} - \frac{7}{12}) : \frac{7}{6} = 2\frac{4}{12} * \frac{6}{7} = 2\frac{1}{3} * \frac{6}{7} = \frac{7}{3} * \frac{6}{7} = \frac{1}{1} * \frac{2}{1} = 2$
$2\frac{4}{15} - 4\frac{1}{5} * (1\frac{5}{6} - \frac{41}{42}) = 2\frac{4}{15} - \frac{21}{5} * (1\frac{35}{42} - \frac{41}{42}) = 2\frac{4}{15} - \frac{21}{5} * (\frac{77}{42} - \frac{41}{42}) = 2\frac{4}{15} - \frac{21}{5} * \frac{36}{42} = 2\frac{4}{15} - \frac{21}{5} * \frac{6}{7} = 2\frac{4}{15} - \frac{3}{5} * \frac{6}{1} = 2\frac{4}{15} - \frac{18}{5} = 2\frac{4}{15} - 3\frac{3}{5} = 2\frac{4}{15} - 3\frac{9}{15} = -1\frac{5}{15} = -1\frac{1}{3}$
$(\frac{2}{15} + 1\frac{7}{12}) * \frac{30}{103} - 2 : 2\frac{1}{4} * \frac{9}{32} = (\frac{8}{60} + 1\frac{35}{60}) * \frac{30}{103} - 2 : \frac{9}{4} * \frac{9}{32} = 1\frac{43}{60} * \frac{30}{103} - 2 * \frac{4}{9} * \frac{9}{32} = \frac{103}{60} * \frac{30}{103} - \frac{8}{9} * \frac{9}{32} = \frac{1}{2} * \frac{1}{1} - \frac{1}{1} * \frac{1}{4} = \frac{2}{4} - \frac{1}{4} = \frac{1}{4}$
$(3\frac{1}{2} : 4\frac{2}{3} + 4\frac{2}{3} : 3\frac{1}{2}) * 4\frac{4}{5} = (\frac{7}{2} : \frac{14}{3} + \frac{14}{3} : \frac{7}{2}) * \frac{24}{5} = (\frac{7}{2} * \frac{3}{14} + \frac{14}{3} * \frac{2}{7}) * \frac{24}{5} = (\frac{1}{2} * \frac{3}{2} + \frac{2}{3} * \frac{2}{1}) * \frac{24}{5} = (\frac{3}{4} + \frac{4}{3}) * \frac{24}{5} = (\frac{9}{12} + \frac{16}{12}) * \frac{24}{5} = \frac{25}{12} * \frac{24}{5} = \frac{5}{1} * \frac{2}{1} = 10$
Пожауйста, оцените решение
