Вычислите:
а) $\frac{27\frac{3}{8} - 21\frac{7}{20}}{(3\frac{4}{7} - 1\frac{23}{28}) - (1\frac{47}{65} - \frac{29}{130})}$;
б) $\frac{4\frac{2}{5} - 3\frac{2}{4} + 8\frac{7}{15} - 8\frac{7}{60}}{2\frac{3}{4} - 4\frac{1}{4}}$.
$\frac{27\frac{3}{8} - 21\frac{7}{20}}{(3\frac{4}{7} - 1\frac{23}{28}) - (1\frac{47}{65} - \frac{29}{130})} = \frac{27\frac{15}{40} - 21\frac{14}{40}}{(3\frac{16}{28} - 1\frac{23}{28}) - (1\frac{94}{130} - \frac{29}{130})} = \frac{6\frac{1}{40}}{(2\frac{44}{28} - 1\frac{23}{28}) - 1\frac{65}{130}} = \frac{\frac{241}{40}}{1\frac{21}{28} - 1\frac{14}{28}} = \frac{241}{40} : \frac{7}{28} = \frac{241}{40} * \frac{4}{1} = \frac{241}{10} = 24,1$
$\frac{4\frac{2}{5} - 3\frac{2}{4} + 8\frac{7}{15} - 8\frac{7}{60}}{2\frac{3}{4} - 4\frac{1}{4}} = \frac{4\frac{24}{60} - 3\frac{30}{60} + 8\frac{28}{60} - 8\frac{7}{60}}{2\frac{3}{4} - 3\frac{5}{4}} = \frac{1\frac{15}{60}}{-1\frac{2}{4}} = -1\frac{1}{4} : 1\frac{1}{2} = -\frac{5}{4} : \frac{3}{2} = -\frac{5}{4} * \frac{2}{3} = -\frac{5}{2} * \frac{1}{3} = -\frac{5}{6}$
Пожаулйста, оцените решение
