Выполните действия:
а) $(1\frac{2}{9} + 1\frac{1}{6}) * (2 - 1\frac{25}{42})$;
б) $(4 + 2\frac{7}{15}) * (10 - 8\frac{16}{23})$;
в) $(4 + 5\frac{1}{6}) * (3\frac{2}{3} - \frac{13}{33})$;
г) $6\frac{5}{12} * \frac{4}{11} - 11\frac{1}{4} * \frac{1}{9}$.
$(1\frac{2}{9} + 1\frac{1}{6}) * (2 - 1\frac{25}{42}) = (1\frac{4}{18} + 1\frac{3}{18}) * (1\frac{42}{42} - 1\frac{25}{42}) = 2\frac{7}{18} * \frac{17}{42} = \frac{43}{18} * \frac{17}{42} = \frac{731}{756}$
$(4 + 2\frac{7}{15}) * (10 - 8\frac{16}{23}) = 6\frac{7}{15} * (9\frac{23}{23} - 8\frac{16}{23}) = 6\frac{7}{15} * 1\frac{7}{23} = \frac{87}{15} * \frac{30}{23} = \frac{87}{1} * \frac{2}{23} = \frac{174}{23} = 7\frac{13}{23}$
$(4 + 5\frac{1}{6}) * (3\frac{2}{3} - \frac{13}{33}) = 9\frac{1}{6} * (3\frac{22}{33} - \frac{13}{33}) = \frac{55}{6} * 3\frac{9}{33} = \frac{55}{6} * \frac{108}{33} = \frac{5}{1} * \frac{18}{3} = \frac{90}{3} = 30$
$6\frac{5}{12} * \frac{4}{11} - 11\frac{1}{4} * \frac{1}{9} = \frac{77}{12} * \frac{4}{11} - \frac{45}{4} * \frac{1}{9} = \frac{7}{3} * \frac{1}{1} - \frac{5}{4} * \frac{1}{1} = \frac{7}{3} - \frac{5}{4} = \frac{28}{12} - \frac{15}{12} = \frac{13}{12} = 1\frac{1}{12}$
Пожауйста, оцените решение
