Найдите значение выражения:
а) $\frac{5}{8} + \frac{1}{4} + \frac{7}{12}$
б) $\frac{5}{6} - \frac{3}{8} + \frac{1}{12}$
в) $\frac{3}{7} + \frac{11}{14} - \frac{2}{21}$
г) $\frac{1}{5} + \frac{1}{7} - \frac{1}{9}$
д) $\frac{13}{18} - \frac{1}{24} - (\frac{29}{72} + \frac{6}{36})$
е) $(\frac{7}{8} - \frac{4}{5}) + (\frac{1}{20} + \frac{1}{4}) + \frac{1}{2}$
$\frac{5}{8} + \frac{1}{4} + \frac{7}{12} = \frac{5}{8} + \frac{2}{8} + \frac{7}{12} = \frac{7}{8} + \frac{7}{12} = \frac{21}{24} + \frac{14}{24} = \frac{35}{24} = 1\frac{11}{24}$
$\frac{5}{6} - \frac{3}{8} + \frac{1}{12} = \frac{10}{12} + \frac{1}{12} - \frac{3}{8} = \frac{22}{24} - \frac{9}{24} = \frac{13}{24}$
$\frac{3}{7} + \frac{11}{14} - \frac{2}{21} = \frac{6}{14} + \frac{11}{14} - \frac{2}{21} = \frac{17}{14} - \frac{2}{21} = \frac{51}{42} - \frac{4}{42} = \frac{47}{42} = 1\frac{5}{42}$
$\frac{1}{5} + \frac{1}{7} - \frac{1}{9} = \frac{7}{35} + \frac{5}{35} - \frac{1}{9} = \frac{12}{35} - \frac{1}{9} = \frac{108}{315} - \frac{35}{315} = \frac{73}{315}$
$\frac{13}{18} - \frac{1}{24} - (\frac{29}{72} + \frac{6}{36}) = \frac{13}{18} - \frac{1}{24} - (\frac{29}{72} + \frac{12}{72}) = \frac{13}{18} - \frac{1}{24} - \frac{41}{72} = \frac{13}{18} - \frac{1}{24} - \frac{41}{72} = \frac{52}{72} - \frac{3}{72} - \frac{41}{72} = \frac{8}{72} = \frac{1}{9}$
$(\frac{7}{8} - \frac{4}{5}) + (\frac{1}{20} + \frac{1}{4}) + \frac{1}{2} = (\frac{35}{40} - \frac{32}{40}) + (\frac{1}{20} + \frac{5}{20}) + \frac{1}{2} = \frac{3}{40} + \frac{6}{20} + \frac{1}{2} = \frac{3}{40} + \frac{12}{40} + \frac{1}{2} = \frac{15}{40} + \frac{1}{2} = \frac{3}{8} + \frac{4}{8} = \frac{7}{8}$
Пожауйста, оцените решение
