Решение:
а) $(-1\frac{1}{3}) * \frac{9}{10} = (-\frac{4}{3}) * \frac{9}{10} = -\frac{4 * 9}{3 * 10} = -\frac{2 * 3}{1 * 5} = -\frac{2 * 3}{1 * 5} = -\frac{6}{5} = -1\frac{1}{5}$;
б) $(-\frac{2}{7}) * 3\frac{1}{2} = (-\frac{2}{7}) * \frac{7}{2} = -\frac{7 * 2}{7 * 2} = -\frac{1 * 1}{1 * 1} = -1$;
в) $(-5\frac{1}{2}) * (-\frac{32}{33}) = (-\frac{11}{2}) * (-\frac{32}{33}) = \frac{11 * 32}{2 * 33} = \frac{1 * 16}{1 * 3} = \frac{16}{3} = 5\frac{1}{3}$;
г) $4\frac{1}{6} * (-\frac{24}{25}) = \frac{25}{6} * (-\frac{24}{25}) = -\frac{25 * 24}{6 * 25} = -\frac{24}{6} = -4$.
Ответ:
а) $-1\frac{1}{5}$;
б) $-1$;
в) $5\frac{1}{3}$;
г) $-4$.