Найдите значение выражения.
1) $1\frac{2}{3} * 3 - (1\frac{1}{3} + 2\frac{2}{9}) * \frac{3}{16} = $
2) $1\frac{3}{5} * 3\frac{1}{3} + (1 - \frac{3}{8}) * (1 - \frac{1}{3}) = $
3) $1\frac{3}{16} * 8 - 2\frac{1}{42} * 2\frac{6}{17} - 1\frac{11}{28} * 1\frac{3}{13} = $
$1\frac{2}{3} * 3 - (1\frac{1}{3} + 2\frac{2}{9}) * \frac{3}{16} = 4\frac{1}{3}$
а) $1\frac{1}{3} + 2\frac{2}{9} = 1\frac{3}{9} + 2\frac{2}{9} = 3\frac{5}{9}$
б) $3\frac{5}{9} * \frac{3}{16} = \frac{32}{9} * \frac{3}{16} = \frac{2}{3} * \frac{1}{1} = \frac{2}{3}$
в) $1\frac{2}{3} * 3 = \frac{5}{3} * 3 = \frac{5}{1} = 5$
г) $5 - \frac{2}{3} = 4\frac{3}{3} - \frac{2}{3} = 4\frac{1}{3}$
$1\frac{3}{5} * 3\frac{1}{3} + (1 - \frac{3}{8}) * (1 - \frac{1}{3}) = 5\frac{3}{4}$
а) $1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8}$
б) $1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3}$
в) $1\frac{3}{5} * 3\frac{1}{3} = \frac{8}{5} * \frac{10}{3} = \frac{8}{1} * \frac{2}{3} = \frac{16}{3} = 5\frac{1}{3}$
г) $\frac{5}{8} * \frac{2}{3} = \frac{5}{4} * \frac{1}{3} = \frac{5}{12}$
д) $5\frac{1}{3} + \frac{5}{12} = 5\frac{4}{12} + \frac{5}{12} = 5\frac{9}{12} = 5\frac{3}{4}$
$1\frac{3}{16} * 8 - 2\frac{1}{42} * 2\frac{6}{17} - 1\frac{11}{28} * 1\frac{3}{13} = 3\frac{1}{42}$
а) $1\frac{3}{16} * 8 = \frac{19}{16} * 8 = \frac{19}{2} = 9\frac{1}{2}$
б) $2\frac{1}{42} * 2\frac{6}{17} = \frac{85}{42} * \frac{40}{17} = \frac{5}{21} * \frac{20}{1} = \frac{100}{21} = 4\frac{16}{21}$
в) $1\frac{11}{28} * 1\frac{3}{13} = \frac{39}{28} * \frac{16}{13} = \frac{3}{7} * \frac{4}{1} = \frac{12}{7} = 1\frac{5}{7}$
г) $9\frac{1}{2} - 4\frac{16}{21} = 9\frac{21}{42} - 4\frac{32}{42} = 8\frac{63}{42} - 4\frac{32}{42} = 4\frac{31}{42}$
д) $4\frac{31}{42} - 1\frac{5}{7} = 4\frac{31}{42} - 1\frac{30}{42} = 3\frac{1}{42}$
Пожауйста, оцените решение