Вычислите:
1) $2 + \frac{1}{1 + \frac{2}{1 + \frac{1}{3}}}$;
2) $\frac{2 - \frac{\frac{1}{2} - \frac{1}{4}}{2}}{2 + \frac{\frac{1}{2} - \frac{1}{4}}{2}}$;
3) $\frac{1}{2 - \frac{1}{2 - \frac{1}{2 - \frac{1}{3}}}}$.
$2 + \frac{1}{1 + \frac{2}{1 + \frac{1}{3}}} = 2 + \frac{1}{1 + \frac{2}{\frac{4}{3}}} = 2 + \frac{1}{1 + \frac{3}{2}} = 2 + \frac{1}{\frac{5}{2}} = 2\frac{2}{5}$
$\frac{2 - \frac{\frac{1}{2} - \frac{1}{4}}{2}}{2 + \frac{\frac{1}{2} - \frac{1}{4}}{2}} = \frac{2 - \frac{\frac{1}{4}}{2}}{2 + \frac{\frac{1}{4}}{2}} = \frac{2 - \frac{1}{8}}{2 + \frac{1}{8}} = \frac{15}{17}$
$\frac{1}{2 - \frac{1}{2 - \frac{1}{2 - \frac{1}{3}}}} = \frac{1}{2 - \frac{1}{2 - \frac{1}{\frac{5}{3}}}} = \frac{1}{2 - \frac{1}{2 - \frac{3}{5}}} = \frac{1}{2 - \frac{1}{\frac{7}{5}}} = \frac{1}{2 - \frac{5}{7}} = \frac{1}{\frac{9}{7}} = \frac{7}{9}$
Пожауйста, оцените решение
