Учебник по математике 6 класс Мерзляк

авторы: А.Г. Мерзляк, В.Б. Полонский, М.С. Якир.

издательство: Вентана-Граф, 2018 г.

Номер №292

7 \frac{7}{9} - 4 \frac{1}{12} + 2 \frac{3}{4} = 7 \frac{28}{36} - 4 \frac{3}{36} + 2 \frac{27}{36} = 5 \frac{52}{36} = 6 \frac{16}{36} = 6 \frac{4}{9}

17 \frac{2}{3} - 6 \frac{1}{36} + 4 \frac{3}{8} = 17 \frac{48}{72} - 6 \frac{2}{72} + 4 \frac{27}{72} = 15 \frac{73}{72} = 16 \frac{1}{72}

10 \frac{9}{16} - (3 \frac{11}{12} + 4 \frac{4}{9}) = 10 \frac{9}{16} - (3 \frac{33}{36} + 4 \frac{16}{36}) = 10 \frac{9}{16} - 7 \frac{49}{36} = 10 \frac{9}{16} - 8 \frac{13}{36} = 10 \frac{81}{144} - 8 \frac{52}{144} = 2 \frac{29}{144}

(20 - 7 \frac{23}{36}) - (14 \frac{4}{27} - 6 \frac{1}{18}) = (19 \frac{36}{36} - 7 \frac{23}{36}) - (14 \frac{8}{54} - 6 \frac{3}{54}) = 12 \frac{13}{36} - 8 \frac{5}{54} = 12 \frac{39}{108} - 8 \frac{10}{108} = 4 \frac{29}{108}