Запишите смешанную дробь в виде неправильной дроби:
а) $1\frac{1}{2}$;
б) $1\frac{1}{3}$;
в) $1\frac{1}{4}$;
г) $1\frac{2}{3}$;
д) $1\frac{3}{4}$;
е) $2\frac{1}{4}$;
ж) $3\frac{1}{5}$;
з) $8\frac{1}{3}$;
и) $2\frac{2}{5}$;
к) $9\frac{5}{7}$;
л) $1\frac{5}{11}$;
м) $1\frac{4}{13}$;
н) $6\frac{1}{12}$;
о) $4\frac{4}{15}$;
п) $12\frac{2}{3}$.
$1\frac{1}{2} = 1 + \frac{1}{2} = \frac{2}{2} + \frac{1}{2} = \frac{2 + 1}{2} = \frac{3}{2}$
$1\frac{1}{3} = 1 + \frac{1}{3} = \frac{3}{3} + \frac{1}{3} = \frac{3 + 1}{3} = \frac{4}{3}$
$1\frac{1}{4} = 1 + \frac{1}{4} = \frac{4}{4} + \frac{1}{4} = \frac{4 + 1}{4} = \frac{5}{4}$
$1\frac{2}{3} = 1 + \frac{2}{3} = \frac{3}{3} + \frac{2}{3} = \frac{3 + 2}{3} = \frac{5}{3}$
$1\frac{3}{4} = 1 + \frac{3}{4} = \frac{4}{4} + \frac{3}{4} = \frac{4 + 3}{4} = \frac{7}{4}$
$2\frac{1}{4} = 2 + \frac{1}{4} = \frac{8}{4} + \frac{1}{4} = \frac{8 + 1}{4} = \frac{9}{4}$
$3\frac{1}{5} = 3 + \frac{1}{5} = \frac{15}{5} + \frac{1}{5} = \frac{15 + 1}{5} = \frac{16}{5}$
$8\frac{1}{3} = 8 + \frac{1}{3} = \frac{24}{3} + \frac{1}{3} = \frac{24 + 1}{3} = \frac{25}{3}$
$2\frac{2}{5} = 2 + \frac{2}{5} = \frac{10}{5} + \frac{2}{5} = \frac{10 + 2}{5} = \frac{12}{5}$
$9\frac{5}{7} = 9 + \frac{5}{7} = \frac{63}{7} + \frac{5}{7} = \frac{63 + 5}{7} = \frac{68}{7}$
$1\frac{5}{11} = 1 + \frac{5}{11} = \frac{11}{11} + \frac{5}{11} = \frac{11 + 5}{11} = \frac{16}{11}$
$1\frac{4}{13} = 1 + \frac{4}{13} = \frac{13}{13} + \frac{4}{13} = \frac{13 + 4}{13} = \frac{17}{13}$
$6\frac{1}{12} = 6 + \frac{1}{12} = \frac{72}{12} + \frac{1}{12} = \frac{72 + 1}{12} = \frac{73}{12}$
$4\frac{4}{15} = 4 + \frac{4}{15} = \frac{60}{15} + \frac{4}{15} = \frac{60 + 4}{15} = \frac{64}{15}$
$12\frac{2}{3} = 12 + \frac{2}{3} = \frac{36}{3} + \frac{2}{3} = \frac{36 + 2}{3} = \frac{38}{3}$
Пожауйста, оцените решение