$\frac{(53\frac{3}{4} + 9\frac{1}{6}) * 1\frac{1}{5}}{(10\frac{3}{10} * 8\frac{1}{2}) * \frac{5}{9}} - \frac{(6\frac{4}{5} - 3\frac{3}{7}) * 5\frac{5}{6}}{3\frac{2}{3} - 3\frac{1}{6}} - 29\frac{5}{6} = \frac{(62 + \frac{3 * 3 + 1 * 2}{12}) * \frac{6}{5}}{(2\frac{3}{10} - \frac{1}{2}) * \frac{5}{9}} - \frac{(3\frac{4}{5} - \frac{3}{7}) * \frac{35}{6}}{\frac{2}{3} - \frac{1}{6}} - 29\frac{5}{6} = \frac{62\frac{11}{12} * \frac{6}{5}}{(1\frac{13}{10} - \frac{5}{10}) * \frac{5}{9}} - \frac{(3\frac{28}{35} - \frac{15}{35}) * \frac{35}{6}}{\frac{4}{6} - \frac{1}{6}} - 29\frac{5}{6} = \frac{\frac{755}{12} * \frac{6}{5}}{\frac{18}{10} * \frac{5}{9}} - \frac{\frac{118}{35} * \frac{35}{6}}{\frac{1}{2}} - 29\frac{5}{6} = \frac{\frac{151 * 5}{6 * 2} * \frac{6}{5}}{\frac{9 * 2}{5 * 2} * \frac{5}{9}} - \frac{\frac{59 * 2}{35} * \frac{35}{3 * 2}}{\frac{1}{2}} - 29\frac{5}{6} = \frac{\frac{151}{2}}{\frac{1}{1}} - \frac{\frac{59}{3}}{\frac{1}{2}} - 29\frac{5}{6} = \frac{151}{2} - \frac{59}{3} * \frac{2}{1} - 29\frac{5}{6} = \frac{151}{2} - \frac{118}{3} - 29\frac{5}{6} = 75\frac{1}{2} - 39\frac{1}{3} - 29\frac{5}{6} = 36\frac{1}{2} - \frac{1}{3} - 29\frac{5}{6} = 36\frac{3}{6} - \frac{2}{6} - 29\frac{5}{6} = 36\frac{1}{6} - 29\frac{5}{6} = 7\frac{1}{6} - \frac{5}{6} = 6\frac{7}{6} - \frac{5}{6} = 6\frac{2}{6} = 6\frac{1}{3}$