Решите уравнение:
1) $7\frac{7}{30} - (5\frac{11}{30} - y) = 3\frac{19}{30}$;
2) $(x - 1\frac{9}{17}) + 2\frac{14}{17} = 5\frac{5}{17}$.
$7\frac{7}{30} - (5\frac{11}{30} - y) = 3\frac{19}{30}$
$-(5\frac{11}{30} - y) = 3\frac{19}{30} - 7\frac{7}{30}$
$5\frac{11}{30} - y = 7\frac{7}{30} - 3\frac{19}{30}$
$-y = 7\frac{7}{30} - 3\frac{19}{30} - 5\frac{11}{30}$
$y = 5\frac{11}{30} + 3\frac{19}{30} - 7\frac{7}{30}$
$y = 1\frac{23}{30}$
$(x - 1\frac{9}{17}) + 2\frac{14}{17} = 5\frac{5}{17}$
$x - 1\frac{9}{17} = 5\frac{5}{17} - 2\frac{14}{17}$
$x = 5\frac{5}{17} - 2\frac{14}{17} + 1\frac{9}{17}$
$x = 4\frac{22}{17} - 2\frac{14}{17} + 1\frac{9}{17}$
$x = 3\frac{17}{17}$
x = 4
Пожауйста, оцените решение