Запишите число в виде неправильной дроби:
1) $4\frac{3}{4}$;
2) $9\frac{6}{11}$;
3) $3\frac{9}{17}$;
4) $12\frac{5}{6}$;
5) $13\frac{49}{100}$;
6) $8\frac{3}{16}$.
$4\frac{3}{4} = 4 + \frac{3}{4} = \frac{16}{4} + \frac{3}{4} = \frac{19}{4}$
$9\frac{6}{11} = 9 + \frac{6}{11} = \frac{99}{11} + \frac{6}{11} = \frac{105}{11}$
$3\frac{9}{17} = 3 + \frac{9}{17} = \frac{51}{17} + \frac{9}{17} = \frac{60}{17}$
$12\frac{5}{6} = 12 + \frac{5}{6} = \frac{72}{6} + \frac{5}{6} = \frac{77}{6}$
$13\frac{49}{100} = 13 + \frac{49}{100} = \frac{1300}{100} + \frac{49}{100} = \frac{1349}{100}$
$8\frac{3}{16} = 8 + \frac{3}{16} = \frac{128}{16} + \frac{3}{16} = \frac{131}{16}$
Пожауйста, оцените решение