Вычислите относительные молекулярные массы веществ, формулы которых $HBr, CO_{2}, C_{4}H_{8}, CS_{2}, N_{2}$ и $C_{3}H_{6}Br_{2}$.
$M_{r}$ (HBr) = 1 * $A_{r}$ (H) + 1 * $A_{r}$ (Br) = 1 * 1 + 1 * 80 = 81.
$M_{r}$ ($CO_{2}$) = 1 * $A_{r}$ (C) + 2 * $A_{r}$ (O) = 1 * 12 + 2 * 16 = 44.
$M_{r}$ ($C_{4}H_{8}$) = 4 * $A_{r}$ (C) + 8 * $A_{r}$ (H) = 4 * 12 + 8 * 1 = 32.
$M_{r}$ ($CS_{2}$) = 1 * $A_{r}$ (C) + 2 * $A_{r}$ (S) = 1 * 12 + 2 * 32 = 90.
$M_{r}$ ($N_{2}$) = 2 * $A_{r}$ (N) = 2 * 14 = 28.
$M_{r}$ ($C_{3}H_{6}Br_{2}$) = 3 * $A_{r}$ (C) + 6 * $A_{r}$ (H) = 2 * $A_{r}$ (Br) = 3 * 12 + 6 * 1 + 2 * 80 = 202.