Дано:
$CaC{O}_3$
Найти:
ω (Ca) − ?
ω (C) − ?
ω (O) − ?
Решение:
Mr ($CaC{O}_3$) = 40 + 12 + 3 * 16 = 100
ω (Ca) = 40 * 1 : 100 * 100% = 40%
ω (C) = 12 * 1 : 100 * 100% = 12%
ω (O) = 16 * 3 : 100 * 100% = 48%
Ответ: ω (Ca) = 40%; ω (C) = 12%; ω (O) = 48%