Рассчитайте относительные молекулярные массы веществ:
$M_{r}$ ($O_{2}$) = _
$M_{r}$ ($Cl_{2}$) = _
$M_{r}$ ($SO_{2}$) = _
$M_{r}$ ($C_{3}H_{6}$) = _
$M_{r}$ ($H_{2}CO_{3}$) = _
$M_{r}$ ($C_{6}H_{12}O_{6}$) = _
$M_{r}$ ($Al_{2}(SO_{4})_{3}$) = _
$M_{r}$ ($O_{2}$) = 2 * $A_{r}$ (O) = 2 * 16 = 32
$M_{r}$ ($Cl_{2}$) = 2 * $A_{r}$ (Cl) = 2 * 35,5 = 71
$M_{r}$ ($SO_{2}$) = $A_{r}$ (S) + 2 * $A_{r}$ (O) = 32 + 1 * 16 = 32 + 32 = 64
$M_{r}$ ($C_{3}H_{6}$) = 3 * $A_{r}$ (C) + 6 * $A_{r}$ (H) = 3 * 12 + 6 * 1 = 36 + 6 = 42
$M_{r}$ ($H_{2}CO_{3}$) = 2 * $A_{r}$ (H) + $A_{r}$ (C) + 3 * $A_{r}$ (O) = 2 * 1 + 12 + 3 * 16 = 2 + 12 + 48 = 62
$M_{r}$ ($C_{6}H_{12}O_{6}$) = 6 * $A_{r}$ (C) + 12 * $A_{r}$ (H) + 6 * $A_{r}$ (O) = 6 * 12 + 12 * 1 + 6 * 16 = 72 + 12 + 96 = 180
$M_{r}$ ($Al_{2}(SO_{4})_{3}$) = 2 * $A_{r}$ (Al) + 3 * $A_{r}$ (S) + 3 * 4 * $A_{r}$ (O) = 2 * 27 + 2 * 32 + 12 * 16 = 310
