Представьте данное уравнение в виде $ax^2 + bx + c = 0$, укажите значения коэффициентов a, b и c:
1) $6x(3 - x) = 7 - 2x^2$;
2) x(x + 1) = (x − 3)(7x + 2);
3) $(5x - 1)^2 = (x + 4)(x - 2)$;
4) 4x(x + 8) − (x − 6)(x + 6) = 0.
$6x(3 - x) = 7 - 2x^2$
$18x - 6x^2 - 7 + 2x^2 = 0$
$-4x^2 + 18x - 7 = 0$
a = −4; b = 18; c = −7.
x(x + 1) = (x − 3)(7x + 2)
$x^2 + x = 7x^2 - 21x + 2x - 6$
$x^2 - 7x^2 + x + 21x - 2x + 6 = 0$
$-6x^2 + 20x + 6 = 0$
a = −6; b = 20; c = 6.
$(5x - 1)^2 = (x + 4)(x - 2)$
$25x^2 - 10x + 1 = x^2 + 4x - 2x - 8$
$25x^2 - 10x + 1 - x^2 - 4x + 2x + 8 = 0$
$24x^2 - 12x + 9 = 0$
a = 24; b = −12; c = 9.
4x(x + 8) − (x − 6)(x + 6) = 0
$4x^2 + 32x - (x^2 - 36) = 0$
$4x^2 + 32x - x^2 + 36 = 0$
$3x^2 + 32x + 36 = 0$
a = 3; b = 32; c = 36.
Пожауйста, оцените решение
