Представьте числа $1, 2, 4, 8, 16, 32, 64, \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \frac{1}{32}, \frac{1}{64}$ в виде степени с основанием:
1) 2;
2) $\frac{1}{2}$.
$1 = 2^0$
$2 = 2^1$
$4 = 2 * 2 = 2^2$
$8 = 2 * 2 * 2 = 2^3$
$16 = 2 * 2 * 2 * 2 = 2^4$
$32 = 2 * 2 * 2 * 2 * 2 = 2^5$
$64 = 2 * 2 * 2 * 2 * 2 * 2 = 2^6$
$\frac{1}{2} = 2^{-1}$
$\frac{1}{4} = \frac{1}{2 * 2} = 2^{-2}$
$\frac{1}{8} = \frac{1}{2 * 2 * 2} = 2^{-3}$
$\frac{1}{16} = \frac{1}{2 * 2 * 2 * 2} = 2^{-4}$
$\frac{1}{32} = \frac{1}{2 * 2 * 2 * 2 * 2} = 2^{-5}$
$\frac{1}{64} = \frac{1}{2 * 2 * 2 * 2 * 2 * 2} = 2^{-6}$
$1 = (\frac{1}{2})^0$
$2 = (\frac{1}{2})^{-1}$
$4 = (\frac{1}{2})^{-2}$
$8 = (\frac{1}{2})^{-3}$
$16 = (\frac{1}{2})^{-4}$
$32 = (\frac{1}{2})^{-5}$
$64 = (\frac{1}{2})^{-6}$
$\frac{1}{2} = (\frac{1}{2})^1$
$\frac{1}{4} = \frac{1}{2} * \frac{1}{2} = (\frac{1}{2})^2$
$\frac{1}{8} = \frac{1}{2} * \frac{1}{2} * \frac{1}{2} = (\frac{1}{2})^3$
$\frac{1}{16} = \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} = (\frac{1}{2})^4$
$\frac{1}{32} = \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} = (\frac{1}{2})^5$
$\frac{1}{64} = \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} = (\frac{1}{2})^6$
Пожауйста, оцените решение
