Найдите корни уравнения:
а) $4x^2 - 9 = 0$;
б) $-x^2 + 3 = 0$;
в) $-0,1x^2 + 10 = 0$;
г) $y^2 - \frac{1}{9} = 0$;
д) $6v^2 + 24 = 0$;
е) $3m^2 - 1 = 0$.
$4x^2 - 9 = 0$
$4x^2 = 9$
$x^2 = \frac{9}{4}$
$x^2 = ±\sqrt{\frac{9}{4}}$
$x = ±\frac{3}{2}$
$x = ±1\frac{1}{2}$
$-x^2 + 3 = 0$
$-x^2 = -3$
$x^2 = 3$
$x^2 = ±\sqrt{3}$
$-0,1x^2 + 10 = 0$
$-0,1x^2 = -10$
$x^2 = 100$
$x^2 = ±\sqrt{100}$
x = ±10
$y^2 - \frac{1}{9} = 0$
$y^2 = \frac{1}{9}$
$y^2 = ±\sqrt{\frac{1}{9}}$
$y = ±\frac{1}{3}$
$6v^2 + 24 = 0$
$6v^2 = -24$
$v^2 = -4$
v − не имеет корней
$3m^2 - 1 = 0$
$3m^2 = 1$
$m^2 = \frac{1}{3}$
$m = ±\sqrt{\frac{1}{3}}$
$m = ±\frac{1}{\sqrt{3}}$
Пожауйста, оцените решение