а) $-\frac{c}{5} + (-\frac{c}{3}) - (-\frac{2c}{5}) - \frac{c}{60}$;
б) $-\frac{p}{5} - (-\frac{2p}{3}) - \frac{p}{4} + (-\frac{p}{60})$.
$-\frac{c}{5} + (-\frac{c}{3}) - (-\frac{2c}{5}) - \frac{c}{60} = (-\frac{12}{60} - \frac{20}{60} + \frac{24}{60} - \frac{1}{60})c = -\frac{9}{60}c = -\frac{3}{20}c$
$-\frac{p}{5} - (-\frac{2p}{3}) - \frac{p}{4} + (-\frac{p}{60}) = (-\frac{12}{60} + \frac{40}{60} - \frac{15}{60} - \frac{1}{60})p = \frac{12}{60}p = \frac{1}{5}p$
Пожауйста, оцените решение
