Вычислите:
$\frac{(\frac{12}{25})^3 * (-1\frac{2}{3})^2}{(-1\frac{1}{5})^2}$.
$\frac{(\frac{12}{25})^3 * (-1\frac{2}{3})^2}{(-1\frac{1}{5})^2} = \frac{(\frac{12}{25})^3 * (\frac{5}{3})^2}{(\frac{6}{5})^2} = \frac{(\frac{2 * 6}{5 * 5})^3 * (\frac{5}{3})^2}{(\frac{6}{5})^2} = \frac{(\frac{2}{5})^3 * (\frac{6}{5})^3 * (\frac{5}{3})^2}{(\frac{6}{5})^2} = (\frac{2}{5})^3 * \frac{6}{5} * (\frac{5}{3})^2 = \frac{2}{5} * (\frac{2}{5})^2 * \frac{6}{5} * (\frac{5}{3})^2 = \frac{2}{5} * (\frac{2}{5} * \frac{5}{3})^2 * \frac{6}{5} = \frac{2}{5} * (\frac{2}{1} * \frac{1}{3})^2 * \frac{6}{5} = \frac{2}{5} * (\frac{2}{3})^2 * \frac{6}{5} = \frac{2}{5} * \frac{4}{9} * \frac{6}{5} = \frac{2}{5} * \frac{4}{3} * \frac{2}{5} = \frac{16}{75}$
Пожауйста, оцените решение
