Функция задана формулой $y = -\frac{2}{3}x$. Заполните таблицу.
$y = -\frac{2}{3}x$
$y(-9) = -\frac{2}{3}x = -\frac{2}{3} * -9 = -2 * -3 = 6$;
$y(-6) = -\frac{2}{3}x = -\frac{2}{3} * -6 = -2 * -2 = 4$;
$y(-3) = -\frac{2}{3}x = -\frac{2}{3} * -3 = -2 * - 1 = 2$;
$y(-2) = -\frac{2}{3}x = -\frac{2}{3} * -2 = \frac{4}{3} = 1\frac{1}{3}$;
$y(-1) = -\frac{2}{3}x = -\frac{2}{3} * -1 = \frac{2}{3}$;
$y(0) = -\frac{2}{3}x = -\frac{2}{3} * 0 = 0$;
$y(1) = -\frac{2}{3}x = -\frac{2}{3} * 1 = -\frac{2}{3}$;
$y(2) = -\frac{2}{3}x = -\frac{2}{3} * 2 = -\frac{4}{3} = -1\frac{1}{3}$;
$y(3) = -\frac{2}{3}x = -\frac{2}{3} * 3 = -2 * 1 = -2$;
$y(6) = -\frac{2}{3}x = -\frac{2}{3} * 6 = -2 * 2 = -4$.
Пожауйста, оцените решение
