Вычислите:
а) $|\frac{1}{12} + \frac{5}{12}|$;
б) $|\frac{1}{12}| + |-\frac{5}{12}|$;
в) $|-\frac{4}{15}| + |-\frac{1}{15}|$;
г) $|-\frac{9}{14}| - |\frac{3}{14}|$;
д) $|1\frac{2}{5}| + |-1\frac{1}{5}|$;
е) $|-2\frac{4}{7}| - |-1\frac{3}{7}|$.
$|\frac{1}{12} + \frac{5}{12}| = |\frac{6}{12}| = |\frac{1}{2}| = \frac{1}{2}$
$|\frac{1}{12}| + |-\frac{5}{12}| = \frac{1}{12} + \frac{5}{12} = \frac{6}{12} = \frac{1}{2}$
$|-\frac{4}{15}| + |-\frac{1}{15}| = \frac{4}{15} + \frac{1}{15} = \frac{5}{15} = \frac{1}{3}$
$|-\frac{9}{14}| - |\frac{3}{14}| = \frac{9}{14} - \frac{3}{14} = \frac{6}{14} = \frac{3}{7}$
$|1\frac{2}{5}| + |-1\frac{1}{5}| = 1\frac{2}{5} + 1\frac{1}{5} = 2\frac{3}{5}$
$|-2\frac{4}{7}| - |-1\frac{3}{7}| = 2\frac{4}{7} - 1\frac{3}{7} = 1\frac{1}{7}$
Пожауйста, оцените решение