Вычислите:
а) $(\frac{165}{182} + \frac{114}{273}) * \frac{91}{186}$;
б) $(\frac{55}{57} - \frac{51}{95}) : \frac{129}{133}$;
в) $1\frac{281}{357} * (\frac{56}{145} - \frac{49}{318})$;
г) $(-\frac{60}{259}) : (-\frac{45}{148} + \frac{75}{222})$.
$(\frac{165}{182} + \frac{114}{273}) * \frac{91}{186} = \frac{165 * 3 + 114 * 2}{546} * \frac{91}{186} = \frac{495 + 228}{546} * \frac{91}{186} = \frac{723}{546} * \frac{91}{186} = \frac{241}{6} * \frac{1}{62} = \frac{241}{372}$
$(\frac{55}{57} - \frac{51}{95}) : \frac{129}{133} = \frac{55 * 5 - 51 * 3}{285} * \frac{133}{129} = \frac{275 - 153}{285} * \frac{133}{129} = \frac{122}{285} * \frac{133}{129} = \frac{122}{15} * \frac{7}{129} = \frac{854}{1935}$
$1\frac{281}{357} * (\frac{56}{145} - \frac{49}{318}) = \frac{638}{357} * \frac{56 * 318 - 49 * 145}{46110} = \frac{638}{357} * \frac{17808 - 7105}{46110} = \frac{638}{357} * \frac{10703}{46110} = \frac{11}{51} * \frac{1529}{795} = \frac{16819}{40545}$
$(-\frac{60}{259}) : (-\frac{45}{148} + \frac{75}{222}) = (-\frac{60}{259}) : \frac{-45 * 3 + 75 * 2}{444} = (-\frac{60}{259}) : \frac{-135 + 150}{444} = (-\frac{60}{259}) : \frac{15}{444} = (-\frac{60}{259}) * \frac{444}{15} = (-\frac{4}{7}) * \frac{12}{1} = -\frac{48}{7} = -6\frac{6}{7}$
Пожауйста, оцените решение
