Вычислите:
1) $3^2 * 1\frac{1}{6}$;
2) $2\frac{2}{3} : 2^3$;
3) $(3,1)^3 + 2,75$;
4) $26 - (2,1)^2$;
5) $(1\frac{1}{2})^2 * 2^3$;
6) $(2\frac{2}{3})^3 : (\frac{2}{3})^2$.
$3^2 * 1\frac{1}{6} = 9 * \frac{7}{6} = 3 * \frac{7}{2} = \frac{21}{2} = 10,5$
$2\frac{2}{3} : 2^3 = \frac{8}{3} : 8 = \frac{8}{3} * \frac{1}{8} = \frac{1}{3}$
$(3,1)^3 + 2,75 = 29,791 + 2,75 = 32,541$
$26 - (2,1)^2 = 26 - 4,41 = 21,59$
$(1\frac{1}{2})^2 * 2^3 = \frac{3}{2} * \frac{3}{2} * 8 = \frac{9}{4} * 8 = 9 * 2 = 18$
$(2\frac{2}{3})^3 : (\frac{2}{3})^2 = (\frac{8}{3} * \frac{8}{3} * \frac{8}{3}) : (\frac{2}{3} * \frac{2}{3}) = \frac{512}{27} * \frac{9}{4} = \frac{128}{3} = 42\frac{2}{3}$
Пожауйста, оцените решение
