Найдите значение выражения:
а) $1\frac{7}{9} + 28 + 2\frac{5}{12} + 5\frac{2}{9} + \frac{7}{12} + 4\frac{3}{4}$;
б) $5\frac{3}{5} - 3,15 + 7\frac{12}{25}$;
в) $8\frac{5}{9} - (4\frac{2}{9} + 2\frac{1}{6})$;
г) $(18\frac{7}{12} + 3\frac{1}{5}) - 7\frac{5}{12}$.
$1\frac{7}{9} + 28 + 2\frac{5}{12} + 5\frac{2}{9} + \frac{7}{12} + 4\frac{3}{4} = 1\frac{7}{9} + 5\frac{2}{9} + 28 + 2\frac{5}{12} + \frac{7}{12} + 4\frac{9}{12} = 6\frac{9}{9} + 28 + 6\frac{21}{12} = 7 + 28 + 6\frac{9}{12} = 42\frac{3}{4}$
$5\frac{3}{5} - 3,15 + 7\frac{12}{25} = 5\frac{15}{25} + 7\frac{12}{25} - 3\frac{15}{100} = 12\frac{27}{25} - 3\frac{15}{100} = 12\frac{108}{100} - 3\frac{15}{100} = 9\frac{93}{100} = 9,93$
$8\frac{5}{9} - (4\frac{2}{9} + 2\frac{1}{6}) = 8\frac{5}{9} - (4\frac{4}{18} + 2\frac{3}{18}) = 8\frac{5}{9} - 6\frac{7}{18} = 8\frac{10}{18} - 6\frac{7}{18} = 2\frac{3}{18}= 2\frac{1}{6}$
$(18\frac{7}{12} + 3\frac{1}{5}) - 7\frac{5}{12} = (18\frac{35}{60} + 3\frac{12}{60}) - 7\frac{5}{12} = 21\frac{47}{60} - 7\frac{5}{12} = 21\frac{47}{60} - 7\frac{25}{60} = 14\frac{22}{60} = 14\frac{11}{30}$
Пожаулйста, оцените решение
