Решение:
а) $-3\frac{2}{5} + (-1\frac{1}{5}) = (-3 - 1) + (-\frac{2}{5} - \frac{1}{5}) = -4 + (-\frac{3}{5}) = -4\frac{3}{5}$;
б) $-7\frac{1}{3} + (-1\frac{2}{3}) = (-7 - 1) + (-\frac{1}{3} - \frac{2}{3}) = -8 - \frac{3}{3} = -8 - 1 = -9$;
в) $-12\frac{5}{7} + (-4\frac{4}{7}) = (-12 - 4) + (-\frac{5}{7} - \frac{4}{7}) = -16 - \frac{9}{7} = -16 - 1\frac{2}{7} = -17\frac{2}{7}$;
г) $-3\frac{8}{19} + (-1\frac{11}{19}) = (-3 - 1) + (-\frac{8}{19} - \frac{11}{19}) = -4 - \frac{19}{19} = -4 - 1 = -5$;
д) $-4\frac{2}{3} + (-1\frac{1}{3}) = (-4 - 1) + (-\frac{2}{3} - \frac{1}{3}) = -5 - \frac{3}{3} = -5 - 1 = -6$;
е) $-8\frac{2}{3} + (-9\frac{2}{3}) = (-8 - 9) + (-\frac{2}{3} - \frac{2}{3}) = -17 - \frac{4}{3} = -17 - 1\frac{1}{3} = -18\frac{1}{3}$.
Ответ:
а) $-4\frac{3}{5}$;
б) $-9$;
в) $-17\frac{2}{7}$;
г) $-5$;
д) $-6$;
е) $-18\frac{1}{3}$.