Упростите выражение:
1) $\frac{2}{3}a + \frac{5}{8}a + \frac{1}{6}a$;
2) $\frac{4}{5}b - \frac{2}{3}b + \frac{4}{15}b$;
3) $\frac{2}{5}x + \frac{4}{7}x - \frac{5}{14}x$;
4) $\frac{7}{12}y - \frac{3}{16}y + \frac{5}{24}y$;
5) $\frac{5}{7}m + \frac{3}{4}m - \frac{5}{8}m$;
6) $\frac{11}{15}c - \frac{5}{18}c - 0,4с$.
$\frac{2}{3}a + \frac{5}{8}a + \frac{1}{6}a = \frac{16}{24}a + \frac{15}{24}a + \frac{4}{24}a = \frac{35}{24}a = 1\frac{11}{24}a$
$\frac{4}{5}b - \frac{2}{3}b + \frac{4}{15}b = \frac{12}{15}b - \frac{10}{15}b + \frac{4}{15}b = \frac{6}{15}b = \frac{2}{5}b$
$\frac{2}{5}x + \frac{4}{7}x - \frac{5}{14}x = \frac{28}{70}x + \frac{40}{70}x - \frac{25}{70}x = \frac{43}{70}x$
$\frac{7}{12}y - \frac{3}{16}y + \frac{5}{24}y = \frac{28}{48}y - \frac{9}{48}y + \frac{10}{48}y = \frac{29}{48}y$
$\frac{5}{7}m + \frac{3}{4}m - \frac{5}{8}m = \frac{40}{56}m + \frac{42}{56}m - \frac{35}{56}m = \frac{47}{56}m$
$\frac{11}{15}c - \frac{5}{18}c - 0,4с = \frac{66}{90}c - \frac{25}{90}c - \frac{36}{90}c = \frac{5}{90}c = \frac{1}{18}c$
Пожауйста, оцените решение