Математика 6 класс Мерзляк Номер 351

Найдите значение выражения:
1)

5 \frac{3}{4} * 8 - 2 \frac{1}{3} * 1 \frac{3}{14} - 1 \frac{37}{48} * 2 \frac{2}{15}

;
2)

1 \frac{3}{22} * 2 \frac{14}{15} - (1 \frac{5}{8} + 2 \frac{1}{8} * \frac{11}{17}) * \frac{3}{7}

;
3)

6 \frac{2}{5} * 1 \frac{9}{16} - (2 \frac{1}{4})^{2}

;
4)

(2 \frac{7}{10} - 1 \frac{8}{15})^{2} * \frac{9}{14}

.

5 \frac{3}{4} * 8 - 2 \frac{1}{3} * 1 \frac{3}{14} - 1 \frac{37}{48} * 2 \frac{2}{15} = \frac{23}{4} * 8 - \frac{7}{3} * \frac{17}{14} - \frac{85}{48} * \frac{32}{15} = \frac{23}{1} * 2 - \frac{1}{3} * \frac{17}{2} - \frac{17}{3} * \frac{2}{3} = 46 - \frac{17}{6} - \frac{34}{9} = 46 - 2 \frac{5}{6} - 3 \frac{7}{9} = 44 \frac{36}{18} - 2 \frac{15}{18} - 3 \frac{14}{18} = 39 \frac{7}{18}

1 \frac{3}{22} * 2 \frac{14}{15} - (1 \frac{5}{8} + 2 \frac{1}{8} * \frac{11}{17}) * \frac{3}{7} = \frac{25}{22} * \frac{44}{15} - (1 \frac{5}{8} + \frac{17}{8} * \frac{11}{17}) * \frac{3}{7} = \frac{5}{1} * \frac{2}{3} - (1 \frac{5}{8} + \frac{11}{8}) * \frac{3}{7} = \frac{10}{3} - (1 \frac{5}{8} + 1 \frac{3}{8}) * \frac{3}{7} = 3 \frac{1}{3} - 3 * \frac{3}{7} = 3 \frac{1}{3} - \frac{9}{7} = 3 \frac{1}{3} - 1 \frac{2}{7} = 3 \frac{7}{21} - 1 \frac{6}{21} = 2 \frac{1}{21}

6 \frac{2}{5} * 1 \frac{9}{16} - (2 \frac{1}{4})^{2} = \frac{32}{5} * \frac{25}{16} - (\frac{9}{4} * \frac{9}{4}) = \frac{2}{1} * \frac{5}{1} - \frac{81}{16} = 10 - 5 \frac{1}{16} = 4 \frac{15}{16}

(2 \frac{7}{10} - 1 \frac{8}{15})^{2} * \frac{9}{14} = (2 \frac{21}{30} - 1 \frac{16}{30})^{2} * \frac{9}{14} = (1 \frac{1}{6})^{2} * \frac{9}{14} = (\frac{7}{6} * \frac{7}{6}) * \frac{9}{14} = \frac{49}{36} * \frac{9}{14} = \frac{7}{4} * \frac{1}{2} = \frac{7}{8}

ГДЗ Математика 6 класс Мерзляк, Полонский, Якир