Найдите сумму:
1) $4\frac{5}{9} + 7\frac{1}{6}$;
2) $6\frac{11}{12} + 8\frac{13}{18}$;
3) $2\frac{3}{16} + 1\frac{7}{24} + 3\frac{1}{12}$.
$4\frac{5}{9} + 7\frac{1}{6} = 11 + \frac{10 + 3}{18} = 11\frac{13}{18}$
$6\frac{11}{12} + 8\frac{13}{18} = 14 + \frac{33 + 26}{36} = 14 + \frac{59}{36} = 14 + 1\frac{23}{36} = 15\frac{23}{36}$
$2\frac{3}{16} + 1\frac{7}{24} + 3\frac{1}{12} = 6 + \frac{9 + 14 + 4}{48} = 6\frac{27}{48} = 6\frac{9}{16}$
Пожауйста, оцените решение
