Решите уравнение:
1) $-\frac{5}{12}x = 0$;
2) 5,4(x + 6,3) = 0;
3) $(x - 3)(x + 4) = 0$;
4) $23,5|x| = 0$.
$-\frac{5}{12}x = 0$
$x = 0 : (-\frac{5}{12})$
x = 0
5,4(x + 6,3) = 0
x + 6,3 = 0
x = −6,3
(x − 3)(x + 4) = 0
x − 3 = 0
$x_1 = 3$;
x + 4 = 0
$x_2 = -4$.
23,5|x| = 0
|x| = 0
x = 0
Пожауйста, оцените решение
