Найдите степень числа:
а) $(\frac{2}{3})^2; (\frac{1}{4})^3; (\frac{5}{4})^2; (\frac{3}{2})^3$;
б) $(1\frac{1}{5})^2; (2\frac{1}{2})^3; (2\frac{1}{3})^2; (3\frac{1}{3})^3$.
$(\frac{2}{3})^2 = \frac{2^2}{3^2} = \frac{4}{9}$;
$(\frac{1}{4})^3 = \frac{1^3}{4^3} = \frac{1}{64}$;
$(\frac{5}{4})^2 = \frac{5^2}{4^2} = \frac{25}{16} = 1\frac{9}{16}$;
$(\frac{3}{2})^3 = \frac{3^3}{2^3} = \frac{27}{8} = 3\frac{3}{8}$.
$(1\frac{1}{5})^2 = (\frac{6}{5})^2 = \frac{6^2}{5^2} = \frac{36}{25} = 1\frac{11}{25}$;
$(2\frac{1}{2})^3 = (\frac{5}{2})^3 = \frac{5^3}{2^3} = \frac{125}{8} = 15\frac{5}{8}$;
$(2\frac{1}{3})^2 = (\frac{7}{3})^2 = \frac{7^2}{3^2} = \frac{49}{9} = 5\frac{4}{9}$;
$(3\frac{1}{3})^3 = (\frac{10}{3})^3 = \frac{10^3}{3^3} = \frac{1000}{27} = 37\frac{1}{27}$.
Пожауйста, оцените решение
