Найдите сумму или разность:
а) $2 - \frac{9}{11}$;
б) $7\frac{2}{5} - 5$;
в) $1\frac{2}{5} - \frac{4}{5}$;
г) $1\frac{1}{8} - \frac{3}{4}$;
д) $2\frac{3}{5} - \frac{2}{3}$;
е) $3\frac{1}{6} - 1\frac{3}{4}$.
$2 - \frac{9}{11} = 1\frac{11}{11} - \frac{9}{11} = 1\frac{2}{11}$
$7\frac{2}{5} - 5 = (7 - 5) + \frac{2}{5} = 2\frac{2}{5}$
$1\frac{2}{5} - \frac{4}{5} = \frac{7}{5} - \frac{4}{5} = \frac{3}{5}$
$1\frac{1}{8} - \frac{3}{4} = \frac{9}{8} - \frac{6}{8} = \frac{3}{8}$
$2\frac{3}{5} - \frac{2}{3} = 2\frac{9}{15} - \frac{10}{15} = 1\frac{24}{15} - \frac{10}{15} = 1\frac{14}{15}$
$3\frac{1}{6} - 1\frac{3}{4} = 3\frac{2}{12} - 1\frac{9}{12} = 2\frac{14}{12} - 1\frac{9}{12} = (2 - 1) + (\frac{14}{12} - \frac{9}{12}) = 1\frac{5}{12}$
Пожауйста, оцените решение