Listen and repeat.
Have a g$\textbf{oo}$d l$\textbf{oo}$k at the c$\textbf{oo}$kery b$\textbf{oo}$k!
Let’s go to the z$\textbf{oo}$ after sch$\textbf{oo}$l. It’s c$\textbf{oo}$l.